(3x^2)+5x-2=288

Solution for (3x^2)+5x-2=288 equation:

(3x^2)+5x-2=288

We move all terms to the left:

(3x^2)+5x-2-(288)=0

We add all the numbers together, and all the variables

3x^2+5x-290=0

a = 3; b = 5; c = -290;
Δ = b2-4ac
Δ = 52-4·3·(-290)
Δ = 3505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{3505}}{2*3}=\frac{-5-\sqrt{3505}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{3505}}{2*3}=\frac{-5+\sqrt{3505}}{6}
$